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3) Efetue os seguintes polinômios :
a) 2a - 3b + 5c +3b -2a -4c+d
b) 3a. (- 2ab )
c) ( x +1 0. ( x-1 )
d) ( a - b ) 2


RESOLVENDO

A) 2a-3b+5c+3b-2a-4c+d
2a-2a-3b+3b+5c-4c+d
c+d
B)3a. (-2ab)
-6a²b
C) (x+10.(x-1)
10x. (x-1)
10x²-10
10x²=10
x²=10/10
x²=1
D) (a-b)2
2a-2b

A) 2a  - 3b + 5c + 3b - 2a - 4c + d > 
2a-2a-3b+3b+5c-4c+d >
c + d
b) 3a(-2ab) =  - 3a²b
c) (x+1)(x-1) = x² - 1² ou x² - 1
d)(a-b)²=  a² - 2ab + b² 
!

Darinha,
\( 2a-3b+5c+3b-2a-4c+d=2a-2a-3b+3b+5c-4c+d\\ \large\boxed{\boxed{2a-3b+5c+3b-2a-4c+d=c+d}}.\\. \)
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\( \large\boxed{\boxed{3a(-2ab)=-6a^2b}}.\\. \)
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\( \large\boxed{\boxed{(x+1)(x-1)=x^2-1}}.\\. \)
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\( (a-b)^2=a^2-2\cdot a\cdot b+(-b)^2\\ \large\boxed{\boxed{(a-b)^2=a^2-2ab+b^2}}.\\. \)
Tenha ótimos estudos)



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